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A heat engine has a hot reservoir of 680°C and a cold reservoir of 220°C. What is the efficiency of the engine
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@danish071996
@Australopithecus
220C = 428F 680C= 1257 F
a 58.3% b 75.9% c 62.3% d 72.1% e 67.6%
grr lol
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\[%\ efficiency\ = (1-\frac{(T_{cold}}{T_{hot}})*100\]
?
This is the formula you need \[efficiency\ percent = (1 - \frac{T_{cold}}{T_{hot}})*100\]
Where Temperature is in kelvin, so add 273 to each of your temperatures.
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