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Mathematics 8 Online
OpenStudy (anonymous):

A heat engine has a hot reservoir of 680°C and a cold reservoir of 220°C. What is the efficiency of the engine

OpenStudy (anonymous):

@danish071996

OpenStudy (anonymous):

@Australopithecus

OpenStudy (hayleymeyer):

220C = 428F 680C= 1257 F

OpenStudy (anonymous):

a 58.3% b 75.9% c 62.3% d 72.1% e 67.6%

OpenStudy (hayleymeyer):

grr lol

OpenStudy (australopithecus):

\[%\ efficiency\ = (1-\frac{(T_{cold}}{T_{hot}})*100\]

OpenStudy (anonymous):

?

OpenStudy (australopithecus):

This is the formula you need \[efficiency\ percent = (1 - \frac{T_{cold}}{T_{hot}})*100\]

OpenStudy (australopithecus):

Where Temperature is in kelvin, so add 273 to each of your temperatures.

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