If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]?
a)29.5
b)30
c)43
d)120

Question

If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]?
a)29.5
b)30
c)43
d)120

geerky42 · Answer

Generally, average rate of change of f(x) in interval [a, b] is $$\large \dfrac{f(b)-f(a)}{b-a}$$

geerky42 · Answer

So here you just have $\dfrac{f(5)-f(1)}{5-1}=~\cdots~?$

bry856 · Answer

what, i dont know how to solve that im sorry

anonymous · Answer

@geerky42 did a good work

rhystic · Answer

you just plug in the 5 value into the equation you have subtract it by the equation with 1 plugged in and then put it over 5-1 which is 4.

anonymous · Answer

nothing left just put the numbers

rhystic · Answer

you're solving wrong. what did you get for 5^3-5 ?

rhystic · Answer

it should be ->( (5^3-5)-(1^3-1))/4