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If f(x)=x^3−x, what is the average rate of change of f(x) over the interval [1, 5]? a)29.5 b)30 c)43 d)120
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Generally, average rate of change of f(x) in interval [a, b] is \[\large \dfrac{f(b)-f(a)}{b-a}\]
So here you just have \(\dfrac{f(5)-f(1)}{5-1}=~\cdots~?\)
what, i dont know how to solve that im sorry
@geerky42 did a good work
you just plug in the 5 value into the equation you have subtract it by the equation with 1 plugged in and then put it over 5-1 which is 4.
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nothing left just put the numbers
you're solving wrong. what did you get for 5^3-5 ?
it should be ->( (5^3-5)-(1^3-1))/4
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