Question

plz help!

Answer 1

What's up!

Answer 2

alrighttty <3

Answer 3

\[\left(\begin{matrix}5x ^{-2}y ^{5} \\ 4x ^{6}y ^{3}\end{matrix}\right)\]

Answer 4

to the \[^{-2}\]

Answer 5

Division? Matrix?

Answer 6

division

Answer 7

So \[\huge( \large \frac{5x^{-2}y^{5}}{4x^{6}y^{3}} \huge )^{\large -2}~\large ?\]

Answer 8

yes

Answer 9

Well first let's apply the exponent outside of the parentheses. We're gonna use two properties to do this. The first is \[\large (\frac{x}{y})^{2}=(\frac{x^{2}}{y^{2}})\] and the second is \[\large (a^{x})^{x}=(a)^{x \times x}\] Do you know how these will be applied?

Answer 10

no

Answer 11

It means that the -2 outside the parentheses will be multiplied by the exponents of both the numerator and denominators.

Answer 12

oh

Answer 13

thank you

Answer 14

Do you think you will be able to take it from there?

Answer 15

yes