Below are two equations. Solve each equation and compare the two solutions. Choose the statement that is true about each solution. Equation 1: |x-4|=6 Equation 2:|3x + 12| = 18 Answer Choices: A. Equation #1 and #2 have the same number of solutions B. Equation #1 has more solutions than Equation #2 C. Equation #1 has fewer solutions than Equation #2 D. None of the statements above describe the number of solutions to equations shown.
Im thinking A but I want to be sure im correct
Yes, they would have the same amount of solutions. You have 2 solutions for the first and 2 for the second.
thats what i got also, thanks for the help! :)
Do you think you could help with one more? @LegendarySadist
\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
And sure, I can help with one more.
Choose the correct description of the graph of the compound inequality: x - 1 less than or greater to 7 or 2x greater than or equal to 22 Do you need answer choices?
\[x - 1 \le 7 or 2x \ge22\]
So \[\large x-1 \leq 7~~or~~2x \geq 22\]
Use ~ to create spaces in Latex :)
yes thats right, sorry im new to this haha
It's ok, I only learned about that yesterday.
Do you need the answer choices?
It'd be easier to see what I'm looking for, yeah.
okay give me a second to type everything out
Kk, sounds good
A: A number line with an open circle on 8,shading to the left, an open circle on 11, shading to the right. B: A number line with an open circle on 8, an open circle on 11, and shading in between. C: A number line with a closed circle on 8, a closed circle on 11, shading in between. D: A number line with a closed circle on 8, shading to the left, and a closed circle on 11, shading to the right.
First distinction we make in the answer choices is that one uses open circles and the other closed circles. Closed circles are used for \[\large \leq ~~and~~ \geq\] while open circles are used for \[\large <~~and~~>\] So that means we can rule A and B out immediately. So our next distinction between C and D is that C has the shading between 8 and 11, while D has \[\large -\infty \leftarrow 8~~and~~11 \rightarrow \infty\] To figure out this one, just plug in a couple of x values, one below 8, one between 8 and 11, and one above 11. Depending on which ones work out will give you the answer.
im confuse a little as to how i add in x values
can you show me an example?
\[\large x-1 \leq 7\\\large 5-1 \leq 7\\\large 4 \leq 7\] Plugged in 5 for x
would the shading be between the numbers or going separate ways?
Well the shading means what x values are acceptable. If only x values between 8 and 11 fit one of the equations, it's between. If only values below 8 or above 11 fit, it would be separate ways.
so it would be C, correct?
Well let me ask you, was 5 an acceptable x? Would 9 be an acceptable x for either of them?
yes 5 was because 7 is greater then 5 but 9 would not be because 9 is greater than 7
So if the shading is between, you're saying that the acceptable x's are 8,9,10, and 11 ONLY. If it's outside, you're saying everything BUT 9 and 10 are acceptable.
Which statement matches the info that we have?
anything under 7 is exceptiable
im sorry im confused
Ok, let's give you a visual representation. Go to www.desmos.com/calculator and plug in the two inequalities.
I just got a straight white line down the middle of two lines
Is it all red except for one small sliver of white?
yes
Well the red is the "shading' in the question.
oh okay i unserstand. so D. because the shading goes seperate ways.
Right, it would be D
Awesome! Thanks so much
\[\huge \color{aqua}N\color{fuchsia}o \space \color{lime}P \color{orange}r \color{blue}o \color{maroon}b \color{red}l \color{olive}e \color{purple}m \ddot\smile \]
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