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Mathematics 7 Online
OpenStudy (mathmath333):

fun question

OpenStudy (anonymous):

?

OpenStudy (mathmath333):

solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2-(5k+4)+7=0\) are equal in magnitude and opposite in sign.

Elsa213 (elsa213):

how is this fun? ;~;

ganeshie8 (ganeshie8):

is there a "x" missing in the middle term of given quadratic equation ?

ganeshie8 (ganeshie8):

\[2x^2-(5k+4)\color{red}{x}+7=0\]

OpenStudy (mathmath333):

let me see ,wait

OpenStudy (mathmath333):

yes u r right x was missing

OpenStudy (mathmath333):

solve for \(y,\ \ y\in \mathbb{R}\) \(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\ \end{align}}\) where roots of \(2x^2-(5k+4)x+7=0\) are equal in magnitude and opposite in sign.

ganeshie8 (ganeshie8):

but how can absolute value be negative ?

OpenStudy (mathmath333):

:)

ganeshie8 (ganeshie8):

oh trick question is it xD \[y\in \emptyset\]

OpenStudy (alekos):

that's exactly what i was wondering

OpenStudy (mathmath333):

initially u fell for the trap

OpenStudy (anonymous):

@ganeshie8 how old are you (exited to know)

ganeshie8 (ganeshie8):

haha that negative symbol is too small to notice

OpenStudy (mathmath333):

haha small little question , no real solution

OpenStudy (mathmath333):

i hope every body understood the trick

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