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OpenStudy (anonymous):
?
OpenStudy (mathmath333):
solve for \(y,\ \ y\in \mathbb{R}\)
\(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\
\end{align}}\)
where roots of \(2x^2-(5k+4)+7=0\) are equal in magnitude and opposite in sign.
Elsa213 (elsa213):
how is this fun? ;~;
ganeshie8 (ganeshie8):
is there a "x" missing in the middle term of given quadratic equation ?
ganeshie8 (ganeshie8):
\[2x^2-(5k+4)\color{red}{x}+7=0\]
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OpenStudy (mathmath333):
let me see ,wait
OpenStudy (mathmath333):
yes u r right x was missing
OpenStudy (mathmath333):
solve for \(y,\ \ y\in \mathbb{R}\)
\(\large \color{black}{\begin{align} |y+k|=-4\hspace{.33em}\\~\\
\end{align}}\)
where roots of \(2x^2-(5k+4)x+7=0\) are equal in magnitude and opposite in sign.
ganeshie8 (ganeshie8):
but how can absolute value be negative ?
OpenStudy (mathmath333):
:)
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ganeshie8 (ganeshie8):
oh trick question is it xD
\[y\in \emptyset\]
OpenStudy (alekos):
that's exactly what i was wondering
OpenStudy (mathmath333):
initially u fell for the trap
OpenStudy (anonymous):
@ganeshie8 how old are you (exited to know)
ganeshie8 (ganeshie8):
haha that negative symbol is too small to notice
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