https://www.dropbox.com/s/im7menys1mzphct/Screenshot%202015-06-10%2011.14.45.png?dl=0
@Michele_Laino
@LegendarySadist
Also, would this count as statistics?
I think it is the weighted average
oh.
The sentence just doesn't make sense to me.
I don't get what it's asking. D:
I think that your exercise is asking for the best value of the quantity which is represented by your distribution here is the value of the weighted average: \[\frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}}\]
i got 65920.590909 :/
Could it just be 66 (i rounded)
no, please here are more steps: \[\begin{gathered} \frac{{2 + 3 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{5 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{34 + 69 + 29}}{{22}} = \frac{{132}}{{22}} = ... \hfill \\ \end{gathered} \]
-3- okay, I will try...to do this
1) 65920.590909 2) 6 3) 6 4) 6
it is 6
:D Yay! Just curious, how did you get all those numbers?
Sorry I have made an error, in reading your values, here is the right weighted average: \[\begin{gathered} \frac{{1 + 2 + 2 \times 3 + 2 \times 4 + 3 \times 5 + 4 \times 6 + 3 \times 7 + 3 \times 8 + 2 \times 9 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{3 + 6 + 8 + 15 + 24 + 21 + 24 + 18 + 11}}{{22}} = \hfill \\ \hfill \\ = \frac{{32 + 69 + 29}}{{22}} = \frac{{130}}{{22}} = ... \hfill \\ \end{gathered} \]
1) 49426.0454545 2) 5.909090 3) 5.909090 4) 5.9090 So, 5.9? or 6
the right result is 5.9, so we can pick 6
namely the right answer is 6
oh yay! Thank you! Thank you! So much!
:)
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