Question

In a lab experiment, a 0.6-g peanut is burned beneath 60 g of water. Heat from the burning peanut raises the water temperature from 22⁰C to 50⁰C in 3.0 minutes. If the heat transfer is 41% efficient, how many Calories of heat did the peanut release while burning? Show all calculations leading to an answer.

Answer 1

@Abhisar

Answer 2

I think this is more probably suitable for physics section.

Answer 3

theres a physics section?

Answer 4

this is definitly physics

Answer 5

you can use the specific heat equation, I'm just not sure where the time comes in

Answer 6

idk either

Answer 7

I really don't think it comes into play because it's asking about energy, not power. It just might be a number thrown in there.

Answer 8

im gonna re enter this in physics

Answer 9

because you don't need the mass of the peanut either

Answer 10

so what do you think i should do @peachpi

Answer 11

I hope this would be answered in the physics section. Good luck! :)

Answer 12

no one is online to help apparently @Sachintha

Answer 13

Find the amount of heat needed to raise the temperature of the water
\[Q = mC(T _{f}-T _{i})\]
\[Q = (60~g)(1~cal/g°C)(50°C-22°C)\]
\[Q = 1,680~cal\]

This is 41% of the heat released by the peanut.
\[0.41x=1680\]
\[x=4,098~cal\]

Answer 14

Exactly what I said. Anyway are you sure about the answer? @peachpi I didn't knew the specific heat capacity of water in calories (knew only in joules) since I didn't know the definition of a calorie. :D

Answer 15

yes because if you work it with C in J/g°C then convert to calories at the end you get the same answer