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Mathematics 7 Online
OpenStudy (anonymous):

I do not understand how to do this.

OpenStudy (anonymous):

Write limn→∞∑k=1n(2+k∗(5/n))3∗5/n as a definite Integral

OpenStudy (tkhunny):

I can't understand the notation. \(\lim_{n\rightarrow \infty}ln(2+k(5/n))^{3}\cdot\dfrac{5}{n}\)?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that is the notation

OpenStudy (tkhunny):

Not quite. What is the "k=" doing in there?

OpenStudy (anonymous):

im not sure thats what my problem says though. Think it stands for constant

OpenStudy (tkhunny):

'k' maybe, but '='?

OpenStudy (anonymous):

oh im sorry let me rewrite equation real quick

OpenStudy (tkhunny):

Maybe you can use the [Draw] feature?

OpenStudy (anonymous):

\[\lim_{n \rightarrow \infty}\sum_{k=1}^{n}(2+k*5/n)^3 *5/n\]

OpenStudy (tkhunny):

Well, that makes more sense!

OpenStudy (tkhunny):

Did you just learn, in that moment, just enough LaTeX to write that? Good work.

OpenStudy (anonymous):

Thank you. Now i am unsure of how to convert that to a definite integral

OpenStudy (tkhunny):

Let's remember the definition of a Riemann Integral. Roughly, you chop things up into smaller and smaller pieces and never stop doing this. This is EXACTLY the function of 'n' in the given expression. \(n \rightarrow \infty\)

OpenStudy (anonymous):

right

OpenStudy (anonymous):

still to not understand how to convert

OpenStudy (tkhunny):

Try a couple values for n and see how it goes.

OpenStudy (anonymous):

what to do you mean try n values?

OpenStudy (tkhunny):

Do n=1, then do n = 2. Look for anything familiar or consistent.

OpenStudy (anonymous):

5*(7k)^3?

OpenStudy (tkhunny):

The first thing I noticed was that \(5/n\) is constant for a given value of n. This suggests an equivalent expression: \(\lim_{n\rightarrow\infty}\dfrac{5}{n}\sum_{k=1}^{n}\left[2+\dfrac{5k}{n}\right]^{3}\)

OpenStudy (anonymous):

yes i agree with that

OpenStudy (anonymous):

and the two is constant

OpenStudy (anonymous):

can you just give me in converted? I like working back from the conversion

OpenStudy (phi):

I think of the 5/n as an increment (e.g. dx ) the k* 5/n ranges from 5/n to 5 for very large n, 5/n is close to 0, so k*5/n represents a variable x going from 0 to 5

OpenStudy (anonymous):

i do not understand what that means

OpenStudy (phi):

It helps if you have the "big picture" of how integration is summation of lots of thin triangles.

OpenStudy (phi):

*rectangles

OpenStudy (tkhunny):

\(=\lim_{x\rightarrow\infty}\dfrac{5}{n}\sum_{k=1}^{n}f\left(\dfrac{5k}{n}\right)\) \(=\lim_{x\rightarrow\infty}\dfrac{b-a}{n}\sum_{k=1}^{n}f(x^{*})\) \(=\int_{0}^{5}f(x)\;dx = \int_{0}^{5}\left(2+5x\right)^{3}\;dx\)

OpenStudy (phi):

I think it's just (2+x)^3 inside the integral

OpenStudy (anonymous):

okay! Thank you

OpenStudy (tkhunny):

Right. Typo. Thanks.

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