I do not understand how to do this.
Write limn→∞∑k=1n(2+k∗(5/n))3∗5/n as a definite Integral
I can't understand the notation. \(\lim_{n\rightarrow \infty}ln(2+k(5/n))^{3}\cdot\dfrac{5}{n}\)?
yes
that is the notation
Not quite. What is the "k=" doing in there?
im not sure thats what my problem says though. Think it stands for constant
'k' maybe, but '='?
oh im sorry let me rewrite equation real quick
Maybe you can use the [Draw] feature?
\[\lim_{n \rightarrow \infty}\sum_{k=1}^{n}(2+k*5/n)^3 *5/n\]
Well, that makes more sense!
Did you just learn, in that moment, just enough LaTeX to write that? Good work.
Thank you. Now i am unsure of how to convert that to a definite integral
Let's remember the definition of a Riemann Integral. Roughly, you chop things up into smaller and smaller pieces and never stop doing this. This is EXACTLY the function of 'n' in the given expression. \(n \rightarrow \infty\)
right
still to not understand how to convert
Try a couple values for n and see how it goes.
what to do you mean try n values?
Do n=1, then do n = 2. Look for anything familiar or consistent.
5*(7k)^3?
The first thing I noticed was that \(5/n\) is constant for a given value of n. This suggests an equivalent expression: \(\lim_{n\rightarrow\infty}\dfrac{5}{n}\sum_{k=1}^{n}\left[2+\dfrac{5k}{n}\right]^{3}\)
yes i agree with that
and the two is constant
can you just give me in converted? I like working back from the conversion
I think of the 5/n as an increment (e.g. dx ) the k* 5/n ranges from 5/n to 5 for very large n, 5/n is close to 0, so k*5/n represents a variable x going from 0 to 5
i do not understand what that means
It helps if you have the "big picture" of how integration is summation of lots of thin triangles.
*rectangles
\(=\lim_{x\rightarrow\infty}\dfrac{5}{n}\sum_{k=1}^{n}f\left(\dfrac{5k}{n}\right)\) \(=\lim_{x\rightarrow\infty}\dfrac{b-a}{n}\sum_{k=1}^{n}f(x^{*})\) \(=\int_{0}^{5}f(x)\;dx = \int_{0}^{5}\left(2+5x\right)^{3}\;dx\)
I think it's just (2+x)^3 inside the integral
okay! Thank you
Right. Typo. Thanks.
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