A rectangular barge 6 m long and 3 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? Show all calculations leading to an answer.

Question

A rectangular barge 6 m long and 3 m wide floats in fresh water.  How much will the barge sink when loaded with 600 kg of sand?  Show all calculations leading to an answer.

anonymous · Answer

Let sink depth=d
 volume of displaced water ...V = 3x 6 x d 
V = 18 d .... is its weight..So,
 18000d kg equals 600 kg....
so d= 0.033 metres
@quick24

anonymous · Answer

@aryandecoolest hey are you still online

anonymous · Answer

yeah

anonymous · Answer

how did you change 18d to 18000 d?

anonymous · Answer

volume is in m^3  and density of water is 1000 kg/m^3

anonymous · Answer

you can do it other way round.
The displaced water occupies about 600/1000=.6m³ 
.6m³/18m².
Both gives you same answer :)
hope it's clear

anonymous · Answer

ok so 600kg is the space the sand occupies in waters place
and v=3x6xd because d=sink depth and we know 18d=v and v=600kg

anonymous · Answer

so therefor 600kg=18d

anonymous · Answer

you know buoyancy.
Buoyancy,h=mg/pglw, l,w = length and width
so h= 6000kg *9.8 m/s^2/1000kg/m^3*9.8m/s^2*6m*3m

anonymous · Answer

h=5880 kg *m/s^2/176400 kg/s^2=1/30m

Hope it's quite clear.