WILL MEDAL AND FAN The formula Q = MCT where Q = heat flow, M = mass, C = specific heat, and T = change of temperature is used to calculate heat flow. Solve this formula for T. T = Q – MC T = Q + MC T = QMC T = Q divided by the quantity M times C
@Michele_Laino
@HelpBlahBlahBlah
@IrishBoy123 could you help?
\(Q = MCT\) you want: \(T = something\) so you're gonna have to start dividing each side by something, right?
ok... yes
so do it!! divide each side by something that gets you T = [the answer] :p
q/t = mc/t?
@IrishBoy123
hi
no :( \(Q = MCT\) \(\frac{Q}{T} = \frac{MCT}{T} = \frac{MC}{1} = MC\) not that helpful, is it? you could try \(\frac{Q}{M} = \frac{MCT}{M} = \frac{CT}{1} = CT\) and do something very similar again
ok... so I am still confused, just a whole bunch of letters
@IrishBoy123
AHH I NEED HELP ASAP
" just a whole bunch of letters" the answer is supposed to be a whole bunch of letters :p and algebra is a whole bunch of letters too it's not easy so don't worry about it - but i cannot just do it for you. someone else might, or someone else might be better at explaining. i'd say go back and look at the bunch of letters and see where we got to just by doing the same thing to each side of the equals sign.
then finish it off
I dont want the answer, I just need to understand it better, and I want you to help me eliminate the wrong answer choices...
we can start from the suggestion of @IrishBoy123 so we can write: \[\Large \frac{Q}{M} = CT\]
@briannam568
i want a medal
now if we divide both sides of that above equation, by C, we get: \[\Large \frac{Q}{{MC}} = \frac{{CT}}{C}\] please simplify @briannam568
ok
how do I simplify that? Ive been trying for twenty minutes? @mathstudent55
@IrishBoy123
on the RHS, you have C on the top and bottom of the fraction. what to do?
you cross it out, since it is canceled out, right?
@Here_to_Help15
@ganeshie8
^Right \[\large \frac{Q}{MC} = \frac{\cancel{C}T}{\cancel{C}}\] So what do you have left?
Q/MC=T!! OHH THANK YOU SOOO MUCH!
"you cross it out, since it is canceled out, right?" indeed, you did it well done
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