Math function rule question
First, look at the points you are given. Do they seem to be linear or not? To see if they are linear, see if the same change in x has the same change in y.
If they are linear, then choose two points and find the equation of the line through them.
There isn't a same change because while Y goes up x2, X goes down randomly
So it's not linear?
can you help me @geerky42
@mathstudent55
No. Don't compare with multiplication. Compare with subtraction.
Try to plot its graph it clarify everything to you
Here are the points: x 2 4 6 y 1 0 -1
I will write the differences between each x-coordinate and the previous one on the line above the x-coordinates. I will do the same for the y-coordinates below the y-coordinates 2 2 x 2 4 6 y 1 0 -1 -1 -1
Notice that as x goes from 2 to 4, the difference is 2. As x goes from 4 to 6, the difference is again 2. Now look at y. As x goes from 2 to 4, y goes down by 1. As x goes from 4 to 6, y again goes down by 1. Every time x increases 2, y decreases 1. That is a linear relation.
x + 2 = y - 1
Now that you see it's a linear relation, pick any two points. Then find the slope of the line between the two points. Do you know how to find the slope of a line given two points on the line?
no please explain
For points \((x_1, y_1)\) and \((x_2, y_2) \), the slope opf the line through those points is: \(slope = m = \dfrac{y_2 - y_1}{x_2 - x_1} \) In other words, subtract the y-coordinates. Subtract the x-coordinates.. Divide the first difference by the second difference.
That gives you slope. Then we have a little more work to find the equation.
just give me a minute
4,0 - 2,1 = -1/2?
or is it 2,1 - 4,0 = 1/2
@mathstudent55
If you use the points (4, 0) and (2, 1), you get: \(m = \dfrac{0 - 1}{4 - 2} = \dfrac{-1}{2} = -\dfrac{1}{2} \)
The slope is -1/2 Now we need to get the equation of the line. The slope-intercept form of the equation of t a line is \(y = mx + b\), where m = slope and b = y-intercept. We know the slope is -1/2. We need to find b. We use one of our 3 points in the equation and solve for b. \(\color{red}{y} = \color{green}{m}\color{blue}{x} + \color{brown}{b}\) Let's use point \((\color{blue}{4}, \color{red}{0})\). We replace \(\color{blue}{x}\) with \(\color{blue}{4} \) and \(\color{red}{y} \) with \(\color{red}{0}\). We replace \(\color{green}{m}\) with \(\color{green}{-\dfrac{1}{2}}\), since \(\color{green}{m}\) is the \(\color{green}{slope}\) and the \(\color{green}{slope}\) is \(\color{green}{- \dfrac{1}{2}} \). \(\color{red}{0} = \color{green}{-\dfrac{1}{2}} (\color{blue}{4}) + \color{brown}{b}\) \(0 = -2 + b\) \(b = 2\) Now that we know b = 2, we can write the equation of the line: \(y = -\dfrac{1}{2}x + 2\)
Join our real-time social learning platform and learn together with your friends!