Question

Solve each equation on the interval [0,2π):
a. 4sin2x – 3 = 0
b. cos(3x) = -1

Answer 1

@freckles @IrishBoy123 @ganeshie8

Answer 2

@peachpi

Answer 3

@Jennjuniper

Answer 4

@johnweldon1993

Answer 5

idk how to do this hun. sorry.

Answer 6

@e.mccormick

Answer 7

it's okay

Answer 8

@e.mccormick is offline btw

Answer 9

@peachpi I'm assuming you don't know how to do this either??

Answer 10

@TheSmartOne @whpalmer4

Answer 11

a. \(4sin2x – 3 = 0\)
thus: \(4sin2x = 3\)
you can finish that off with your calculator. solve for '2x' first.

Answer 12

Wait, so do I solve 4sin(2x) with my calculator? What about the " = 3" that you put. Should the answer to 4sin(2x) be my answer to "a"? What about b? @IrishBoy123

Answer 13

@poopsiedoodle

Answer 14

@sammixboo

Answer 15

@GenTorr

Answer 16

can yo u help with my questinon

Answer 17

i can try

Answer 18

@logan6767 depends on what your question is...

Answer 19

Which of the following points lie in the solution set to the following system of inequalities?

y less than or greater to x - 5
y less than or greater to -x - 4

Answer 20

(1, 10)
(-1, 10)
(10, 1)
(1, -10)

Answer 21

@dumbcow

Answer 22

Sorry, can't solve it @logan6767

Answer 23

@jim_thompson5910

Answer 24

4 sin (2x) - 3 = 0
4 sin (2x) = 3
sin (2x) = 3/4

2x = arcsin (3/4) → this is the 1st quadrant solution for 2x
x = ½ arcsin (3/4)

2x = π - arcsin (3/4) → this is the 2nd quadrant solution for 2x
x = ½(π - arcsin (3/4))

If 0<x<2π, then 0<2x<4π, so other solutions for 2x are

2x = 2π + arcsin (3/4)
x = π + ½ arcsin (3/4)

2x = 3π - arcsin (3/4)
x = ½(3π - arcsin (3/4))

Answer 25

Is this correct or are you guessing??

Answer 26

and I'm out

Answer 27

what about b?

Answer 28

So a has 6 solutions?:
2x = 2π + arcsin (3/4)
x = π + ½ arcsin (3/4)

2x = 3π - arcsin (3/4)
x = ½(3π - arcsin (3/4))
x = ½ arcsin (3/4)
x = ½(π - arcsin (3/4))

Or 4 solutions?:
x = π + ½ arcsin (3/4)
x = ½(3π - arcsin (3/4))
x = ½ arcsin (3/4)
x = ½(π - arcsin (3/4))

@peachpi

Answer 29

4

Answer 30

okay, but what about b??

Answer 31

The angle here is 3x, so the interval is [0, 6π).
Pull out your unit circle and find the angle that has a cosine of -1.
Then add 2π twice to get the other 2 solutions

Answer 32

Do I add 2pi to the -1 or to the angle that has a cosine of -1?