Question

The table shows the results of rolling a number cube, with sides labeled 1 through 6, several times.

What is the experimental probability of rolling a 2 or a 4?

Express your answer in simplest form.

Outcome 1 2 3 4 5 6
Number of times outcome occurred 10 6 4 8 6 6

Answer 1

@peachpi @Mahmood786123

Answer 2

gimme a sec

Answer 3

just add all the values up! A 1 was rolled 10 times, a 2 was rolled 6 times...how many "times" were there total?

Answer 4

im thinking it 2/5

Answer 5

94

Answer 6

Where's the 94 coming from? I get 40!

When you're calculating probability, you want to find how often your outcome of interest occurs out of the total number of outcomes that actually occur. I'm trying to get you to calculate each individually, starting with the total number of outcomes.

The number cube was rolled a bunch of times. Each roll is called a trial. The number that was rolled was recorded for each trial performed. In the end, 10 trials rolled a 1, 6 trials rolled a 2, and so on through 6.

The total number of trials can be found by adding all the trials that resulted in each outcome, so:

10+6+4+8+6+6=40

There were 40 trials/rolls in total. Of those 40 rolls, we want to know how often a 3 or a 6 popped up. According to the table, 4 rolls resulted in a 3, and 6 rolls resulted in a 6, so out of the 40 rolls, our outcome of interest (a 3 or a 6) occurred 4+6=10 times.

That means the experimental probability (the probability based on this particular experiment) of rolling a 3 or a 6 is 10/40, or 1/4.

Does that makes sense?

Answer 7

i need a fraction

Answer 8

It's just a matter of understanding the situation you're given. For these kinds of questions, always try to follow the procedure I explained above!

Answer 9

1/4

Answer 10

thx mahmood

Answer 11

your welcome

Answer 12

hope I helped :)

Answer 13

u think u can help with 5 more

Answer 14

i'll try but I might need to leave soon

Answer 15

ok imma close this then reopen

Answer 16

ok