2y+3/y = 3/2 rational expression help
@Ashleyisakitty @poopsiedoodle @whpalmer4 @blahhedup101
are you trying to solve an equation?
\[2y+\frac{3}{y}=\frac{3}{2} \\ \text{ multiply both sides by } y \neq 0 \\ y(2y+\frac{3}{y})=y(\frac{3}{2} )\\ y(2y)+y(\frac{3}{y})=\frac{3}{2}y \\ 2y^2+3=\frac{3}{2} y \\ \text{ if you don't want \to deal with any fractions multiply both sides by 2 } \\ 4y^2+6=3y \\ \text{ subtract} 3y \text{ on both sides } 4y^2-3y+6=0\] you have a quadratic equation to solve. but the equation you wrote is probably not the equation you meant you probably meant \[\frac{2y+3}{y}=\frac{3}{2}\] though I could be wrong about that too you did say rational expression after all and you have an equation composed of rational expressions on left and right side
and if you meant the last equation I wrote which is (2y+3)/y=3/2 I would still multiply both sides by y and 2
\[2(2y+3)=3(y) \\ 4y+6=3y \]
@freckles than what
you solve for y
And I still don't know what equation you mean
@freckles The second equation you showed
ok do something to get your y terms on one side
@freckles Thanks
what did you get?
\[2(2y+3)=3(y) \\ 4y+6=3y\] You subtracted 4y on both sides right?
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