Question

HELLP MEEE PLEASEE!!!!!
find the slope and the y-intercept of the equation y-3(x-1)=0

Answer 1

The slope-intercept form of a line is

\[\large y =mx + b\]

So we need to make our expression look like that

\[\large y - 3(x - 1) = 0\]

Where would be start?

Answer 2

find what x is equal to I guess

Answer 3

Not nearly as complicated, all we need to do is rearrange our equation so that y = something since y = mx + b is the form we want

So from

\[\large y-3(x-1) = 0\] the first step would be to distribute that 3 into the parenthesis...we want to simplify this a bit

Answer 4

so it would be 3x-3

Answer 5

Well yes it could be...normally we would distribute the minus sign with it but that's okay..but we have to make sure that now we have

\[\large y - (3x - 3) = 0\]

right? What would be next...remember we want y = ...

Answer 6

so do I multiply 0*3x or 0*3

Answer 7

No we dont need to multiply at all here

\[\large y - (3x - 3) = 0\]

If the only thing stopping us from having that y = something is a \(\large -(3x - 3)\) then all we have to do is add it to the other side

\[\large y \cancel{- (3x - 3) + (3x - 3)} = 0 + (3x - 3)\]

\[\large y = ?\]

Answer 8

so y=-3 srry im kind of clueless

Answer 9

No dont worry about it algebra is always tricky in the beginning, actually depending on what you just asked then you're right or wrong lol

Well....if we have \(\large y = 0 + (3x - 3)\) that just means we have

\[\large y = 3x - 3\] right?

So the slope would be? the y-intercept would be?

Answer 10

ok so the slope would be 3 and the y-intercept is -3

Answer 11

Perfect!