Question

solve

Answer 1

\(\large \color{black}{\begin{align} |x-3|+|x+4|+|x-1|=14\hspace{.33em}\\~\\
\end{align}}\)

Answer 2

I get x = 14/3 and -14/3

Answer 3

Is this a test?

Answer 4

how get that

Answer 5

this is no test

Answer 6

well first we take all the positive values within the modulus

(x-3) + (x+4) + (x-1) =14 and solve for x

Answer 7

best way to do this problem is partitioning the x's

Answer 8

then we take all the negative values

-(x-3) - (x+4) - (x-1) =14 and solve for x

Answer 9

there will be total of 6 cases but that is a long way

Answer 10

if you plot the graph you'll see that there are only two values

Answer 11

that can be if 4 values are not valid

Answer 12

that's right. the 4 values are not valid

Answer 13

just plot the graph and you'll see

Answer 14

i look for a pen paper method

Answer 15

that's fine, you can do it that way. But Desmos is easier

Answer 16

Hey, yes, just do it casewise.

Answer 17

u mean take 6 cases ?

Answer 18

You'd need five, so yes.

Answer 19

how is it 5 cases

Answer 20

It's 4 cases

Answer 21

Oh, four.

Answer 22

For some reason, I thought there were four absolute values. Oops.