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limit definition for \(f'(x)\) is\[f'(x)=\lim_{h \to 0} \frac{f(x+h)-f(x)}{h}\]have you tried it?
Im not sure how to do that equation
If \(f(x)=4.5x^2-3x+2\), then \(f(x+h)=4.5(x+h)^2-3(x+h)+2\). Agreed? From the definition, you have \[\begin{align*}f'(x)&=\lim_{h\to0}\frac{\overbrace{(4.5(x+h)^2-3(x+h)+2)}^{f(x+h)}-\overbrace{(4.5x^2-3x+2)}^{f(x)}}{h}\\\\ &=\lim_{h\to0}\frac{4.5x^2+9xh+4.5h^2-3x-3h+2-4.5x^2+3x-2}{h}\\\\ &\vdots\end{align*}\]
Yes
Simplify the fraction and take the limit.
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