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Please Help! Simplify the trigonometric expression
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\[ \frac{ \sin ^{2} \theta }{ 1-\cos \theta }\]
Answers:
Write sin² Θ as 1 - cos² Θ then factor
I'm not sure how to
1 - cos² Θ is a difference of squares. Factoring it follows the pattern a² - b² = (a + b)(a - b) So a = 1 and b = cos Θ
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alright
\[1-1 = (1+\cos \theta)(1-\cos \theta)\]
1 - cos² Θ = (1 + cos Θ)(1 - cos Θ)
ohhhhh ok I see now
ya I messed up on the b^2 oops...
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so now what?
that's the numerator. Cancel what you can with the denominator and see what's left
oohhh is the answer \[1+\cos \theta \]
yes
so A?
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yes
thank you
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