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A triangular lot bounded by three streets has a length of 300 feet on one street, 250 feet on the second, and 420 feet on the third. Find the measure of the largest angle formed by these streets. Which of the following equations can be used to solve the problem?
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looks like a law of cosines problem. The largest angle is opposite the longest side
thanks
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yea..... idk how to do this, i know that the equation is\[c^2=a^2+b^2-2ab(cosC)\] but i don't know how to apply it.
|dw:1434124669566:dw| Let's say this is our triangle a, b, and c are the lengths and A, B, C are angles
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