Question

Ok, I'm not sure if I am doing this problem right. Let G(x)=5/(x-2)^2. Find the lim x 2 G(x). I used 2 in the equation. so I got G(x)=5/(2-2)^2. the answer comes up as undefined.

Answer 1

HI!!

Answer 2

it is really
\[\lim_{x\to 2}\frac{5}{(x-2)^2}\]?

Answer 3

yes

Answer 4

then since the denominator goes to zero and the numerator does not, there is no limit

Answer 5

Doesn't the deniminator approach zero but not gat there so the limit is infinity.?

Answer 6

thank you @misty1212