Question

A radioactive isotope has a half-life of one week. How much of it will remain after one month? Show all calculations leading to an answer OR explain your answer with 3 – 4 complete sentences.

Answer 1

@hugekabab

Answer 2

ooo half life ... its been a while since i did these ... let me think

Answer 3

ok

Answer 4

ok listen closely

Answer 5

assume that the isotope starts at x units

Answer 6

. after 1 week half will be gone, or x/2, after the second week half of what remains will be gone. x/2 /2 or x/4, after three weeks x/8 and after 4 weeks, x/16 or 1/16 of the starting amount

Answer 7

get it ?

Answer 8

yes i kinda already understood half life basically each weach this isotope will loose half of it total life left

Answer 9

yup

Answer 10

btw i gotta ask ... is this for hig school ?

Answer 11

so
W1=1/2
W4=1/16

Answer 12

so at 1 month it will have 1/16 of its life

Answer 13

thats what i think

Answer 14

ok thank you

Answer 15

half of the orignal in the first week ... half of the half left in the second week (quater of the orignal) and so on

Answer 16

get the sequence ?

Answer 17

and just to clarify on the last question we did i divided those numbers and got 60041537135.7 and i add KG-J

Answer 18

yes i got it thank you so much

Answer 19

just kg .... cause its just simple mass ... nothing more ..and btw ... do the math again just to be sure yu have the figures right ..

Answer 20

i was kinda hoping for a medal ...its like my first time here on open study ... and damn is this place cool

Answer 21

i literally divided the two as is

Answer 22

yeah yu did multiply it by C right ? the speed of light

Answer 23

yu did right ... as long as you multiplied C as well

Answer 24

no i divided
m=e/c^2

Answer 25

yeah divide ...sorry my bad

Answer 26

its correct thrn

Answer 27

then *

Answer 28

C must be in m/s

Answer 29

and what about the ^2 over c? is that encompassed in the number i used for the speed of light

Answer 30

yes .. thats the speed of light squared

Answer 31

ok

Answer 32

well thank you than

Answer 33

no problem ... always happy to help ..