Please help with this. Thank you!

Question

anonymous · Answer

attachment

anonymous · Answer

@ganeshie8

astrophysics · Answer

$$x^2-4 \implies (x-2)(x+2)$$

astrophysics · Answer

$$\frac{ 5 }{ x-2 } - \frac{ 20 }{ (x-2)(x+2) } = 1$$ now you may use rule $$\frac{ a }{ b } - \frac{ c }{ d } = \frac{ ad-bc }{ bd }$$

anonymous · Answer

yeah so there can be infinite solution but u cant try it out maybe is there a formula to find it out ?

astrophysics · Answer

It is not infinite solutions :P

anonymous · Answer

how do u know it :/

astrophysics · Answer

An equation would have infinite many solutions if the equation has equal values for all variables. So if we had something such as y = x, unless stated otherwise.

anonymous · Answer

buuuuuuuuuuuutt theres only one unknown right

astrophysics · Answer

Lets keep going, so we don't make mistakes, any idea kitty?

anonymous · Answer

Well from what I'm doing, it's turn out to be answer B...:(

astrophysics · Answer

Well lets see...if we simplify it a bit more we should get $$5(x+2)-20=(x-2)(x+2) \implies 5x-10=x^2-4 \implies x^2-5x+6 = 0$$ do you know how to factor?

astrophysics · Answer

I don't think you do, I think you're just guessing, if you factor $$x^2-5x+6=0$$ you will get your answer.

usukidoll · Answer

there can be only one unknown? really?  Last time I checked there are math problems that make you solve for 3 unknowns. x=? y = ? z = ? 
Factoring out that equation in this case, gives out more than one x = ?

astrophysics · Answer

I think they just assumed it before doing the math :P

usukidoll · Answer

*facepalm* which is a big no-no.