Question

CENTER OF MASS

Answer 1

A 1.00 kg particle has the xy coordinates (-1.00 m, 1.00 m) and a 2.00 kg particle has the xy coordinates (0.800 m, -0.800 m). Both lie on a horizontal plane. At what (a) x and (b) y coordinates must you place a 3.00 kg particle such that the center of mass of the three-particle system has the coordinates (-0.400 m, -0.500 m)?

Answer 2

kindly help

Answer 3

@zepdrix

Answer 4

i just need help with this Q and nothing more.

Answer 5

i know the formula its Xcm= m1x1+m2x2+m3x3/m1+m2+m3

Answer 6

@UsukiDoll @ganeshie8

Answer 7

I don't know science related problems sorry

Answer 8

***i know the formula its Xcm= m1x1+m2x2+m3x3/m1+m2+m3***

fill in the information you know into that formula. You know numbers for almost all the variables.

Answer 9

1.00 kg with coords (-1.00 m, 1.00 m) : m1= 1 , x1= -1
2.00 kg with coords (0.800 m, -0.800 m). m2=2 , x2=0.8
3.00 kg particle m3= 3, x3 unknown
center of mass (-0.400 m, -0.500 m) Xcm -0.4

Answer 10

oka thankyou