Question

find the distance of the line 5x-12y = 26 from (1,5)

Answer 1

Hi there, here is the well known formula for the distance of a point (x,y) from a line:

\[Distance(ax+by+c=0,(x_{0}y _{0})):\]

So in our case the point is (1,5) and the line is : 5x-12y-26=0 so directly putting values in the formula we get:

\[distance=\frac{ \left| 5x1-12x5-26 \right| }{ \sqrt{(5^{2}+12^{2})} }\]

Answer 2

Can you solve from here @martaamador62

Answer 3

Seems like you left but i will finish it off for you :D
So we solve

\[Distance=\frac{ \left| 5-60-26 \right| }{ \sqrt{(169)} }\]

5-60=-55
-55-26=-81

sqrt 169=13

\[distance=\frac{ \left| -81 \right| }{ 13}=\frac{ 81 }{ 13 }\]

Answer 4

Thank you @jagr2713 :) and i'm so sorry i didn't immediately responded to this question i fell asleep :)))