10% pins are defective, if 10 pins are selected at random calculate the probability that exactly 3 are defective?

Question

johnweldon1993 · Answer

This would be a binomial process

We would count a "success" as a pin being defective

n = 10
p = 0.1
x = 3

So if we have a calculator *if not let me know* we could always just use the "binompdf" function

$$\large binompdf(10,0.1,3)$$

anonymous · Answer

i have  my final ppr on friday , i need help in studying statistics please help me out.

anonymous · Answer

this qusetion has  3 parts ?
1, exactly 3 are defective 
2, more than 3 are defective  
3, less than mean number are defective ?