Question

SOMEONE PLEASE HELP ME WITH A FEW QUESTIONS

Answer 1

The tangent-secant theorem: \(CD^2 = CB \times CA\)

Answer 2

@kc_kennylau Can you help me through the problem?

Answer 3

@kc_kennylau

Answer 4

Or anyone that can help please.

Answer 5

i'll help! :)

Answer 6

let's use the formula @kc_kennylau provided :3
\[CD^2 = BC+ AC\]

Answer 7

@Liv1234 u there?

Answer 8

Sorry, yes I'm here.

Answer 9

@Godlovesme that was times

Answer 10

Thank you for helping by the way.

Answer 11

oh sorry :/

Answer 12

it's alright

Answer 13

So, how would I use the formula to find out the answer?

Answer 14

@Godlovesme @kc_kennylau

Answer 15

Well, you have the length of \(CD\) and \(CB\)

Answer 16

So, 30*17?

Answer 17

Well, the formula is \(CD^2 = CB\times CA\)

Answer 18

Ohh, so 30^2=17*CA?

Answer 19

Yes :DDDD

Answer 20

A!

Answer 21

Can you help me with another question(:

Answer 22

No it's not A

Answer 23

A is actually the length of \(CA\)

Answer 24

You're asked to find the length of \(BA\)

Answer 25

Yes, it is because 30^2=900 and 17*52.9=900, right?

Answer 26

Ohh I see what you're saying sorry my bad.

Answer 27

it's alright xd

Answer 28

So, where did I mess up though?

Answer 29

Well, you only found the length of \(CA\).

Answer 30

How do you find the length of \(BA\) from that?

Answer 31

Divide by half?

Answer 32

Well, we can see that \(CA - CB = BA\)

Answer 33

Ohh, so 30-17?

Answer 34

Um.... no

Answer 35

Remember that \(CA = 52.9\)

Answer 36

Ohhh okay oopsies. cx

Answer 37

It's 35.9! Because 52.9-17=35.9

Answer 38

:D

Answer 39

yes :D

Answer 40

Can you help me again??

Answer 41

of course

Answer 42

Well, can you tell me \(m\angle OAB\)?

Answer 43

No, I don't understand it. :/ (and by the way I need help with like 3 other questions after this one if that's okay)

Answer 44

I mean the angle \(OAB\)

Answer 45

I don't know how to find it out that's what I'm confused about.

Answer 46

Well, since \(AB\) is tangent, the angle is actually \(90^\circ\)

Answer 47

Okay, so what do we do from there?

Answer 48

So, we can actually apply the Pythagoras' Theorem

Answer 49

Ohh okay. So, what was the formula for that?

Answer 50

\(OA^2+AB^2=OB^2\)

Answer 51

So, 24^2+AB^2=OB^2?

Answer 52

Did I put the numbers in wrong?

Answer 53

Nope

Answer 54

Can we find \(OC\)?

Answer 55

I think we can, but I'm not sure how.

Answer 56

Well, it is another radius

Answer 57

All radius have the same length

Answer 58

So, what would it be then?

Answer 59

I mean the radius.

Answer 60

Hello?

Answer 61

Well

Answer 62

\(OA\) is another radius

Answer 63

Ohh, so 90?

Answer 64

Em... what are we talking about?

Answer 65

The radius?

Answer 66

Well, the radius is 24

Answer 67

Oh okay, so OC would be 24?

Answer 68

Yes :D

Answer 69

So how long is \(OB\)?

Answer 70

24!

Answer 71

em.. i'm talking about \(OB\)

Answer 72

Ohh, oops.

Answer 73

I'm not sure what it would be, is there a way to find out?

Answer 74

Well, OB is just OC + CB

Answer 75

Would it be 48?

Answer 76

Nope. CB is actually 27

Answer 77

27+24=51

Answer 78

So, would the answer to the question be 51?

Answer 79

Nope, we need to find \(AB\)

Answer 80

And we'd do that by?

Answer 81

the pythagoras' theorem! :D

Answer 82

Ohh. And what was the formula again aha?

Answer 83

\(OA^2+AB^2=OB^2\)

Answer 84

So, 27^2+AB^2=51^2. 51^2=2601. Right?

Answer 85

I might have messed up with that a little.

Answer 86

it should be 24^2 instead of 27^2

Answer 87

Ohh okay. 24^2+AB^2=51^2.

Answer 88

:)

Answer 89

It would be 45. Which is A. Can you help me again?(:

Answer 90

Well, it's difficult to discuss without names

Answer 91

What do you mean?

Answer 92

Without names of vertices

Answer 93

I can't refer any line