three cards are drawn from an ordinary deck of 52 cards. each card is replaced in the deck before the next card is drawn. what is the probability that at least one of the cards was a spade
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OpenStudy (anonymous):
Ok first how many spades are in a deck of cards
OpenStudy (anonymous):
13
OpenStudy (anonymous):
52C3
OpenStudy (anonymous):
soo divde 52 cards by 13 cards
OpenStudy (anonymous):
what do i put in the numerator?
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OpenStudy (anonymous):
it says at least 1 spade so im confused
OpenStudy (anonymous):
round it to the nearest whole number
OpenStudy (anonymous):
P = 1 - P(no spade cards)
OpenStudy (anonymous):
im so confused now lol
OpenStudy (anonymous):
at least 1 spade card means P(1 spade) + P(2 spades) + P(3 spades). If you do this way, you'd have to calculate 3 times. But instead, just calculate the complement and subtract from 1
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OpenStudy (anonymous):
wont i get a negative number if i subtract from 1?
OpenStudy (anonymous):
No, you won't
OpenStudy (anonymous):
what
OpenStudy (anonymous):
what would you get if you do P(no spade cards) ?
OpenStudy (anonymous):
39/52
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