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Mathematics 13 Online
OpenStudy (anonymous):

Thanks!

OpenStudy (michele_laino):

we have to apply this formula: \[\Large \frac{{f\left( 7 \right) - f\left( 4 \right)}}{{7 - 4}}\]

OpenStudy (anonymous):

\[\frac{ f(3) }{ 3}\] So it would be?

OpenStudy (michele_laino):

no, you have to substitute the expression of your function, like below: \[\large \begin{gathered} \frac{{f\left( 7 \right) - f\left( 4 \right)}}{{7 - 4}} = \hfill \\ \hfill \\ = \frac{{\left( {2 \times {7^2} - 16 \times 7 + 57} \right) - \left( {2 \times {4^2} - 16 \times 4 + 57} \right)}}{3} \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

Would the average rate of change be 6?

OpenStudy (anonymous):

So I had to plug in 4 and 4 into the original equation, then subtract them from each other and divide it by 3?

OpenStudy (anonymous):

I meant plug in 7 and 4

OpenStudy (michele_laino):

you have to plug in 7 and 4, so, the next step is: \[\large \begin{gathered} \frac{{f\left( 7 \right) - f\left( 4 \right)}}{{7 - 4}} = \hfill \\ \hfill \\ = \frac{{\left( {2 \times {7^2} - 16 \times 7 + 57} \right) - \left( {2 \times {4^2} - 16 \times 4 + 57} \right)}}{3} = \hfill \\ \hfill \\ = \frac{{ - 14 + 32}}{3} = ...? \hfill \\ \end{gathered} \]

OpenStudy (anonymous):

\[\frac{ 18 }{ 3}\] Then simplified to 6?

OpenStudy (michele_laino):

that's right!

OpenStudy (anonymous):

Thank you!!

OpenStudy (michele_laino):

:)

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