Question

HELP PLEASE WILL MEDAL!!!!
What is the standard form of the equation of the circle in the graph? https://prwi7873-stonewall-ccl.gradpoint.com/Resource/5711966,90A,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc093-1.jpg

Answer 1

@Deadpool117

Answer 2

No fuking clue.. sorry kid

Answer 3

Yea.. its pretty hard XD its okay thanks for tryig

Answer 4

no problem

Answer 5

@acxbox22

Answer 6

@BlossomCake

Answer 7

Ok, I can help. :)

Answer 8

Standard form of a circle is \[\large (x-h)^{2}~+~(y-k)^{2}=r^{2}\] h and k represent the point of the center of the circle and r is the radius.

Answer 9

Yes I know that , I just SUCK at graphs so I have no clue what the h k or r is x.x

Answer 10

"h and k represent the point of the center of the circle and r is the radius." To be a bit clearer, the center point of the circle is (h,k).

Answer 11

so the center of that graph is (-4,0)?

Answer 12

The opposite. It's (0,-4)

Answer 13

oops yea saw that , sorry brain dead when it comes to graphing for some reason XD

Answer 14

x^2+(y-4)^2=16 , is what i think it is

Answer 15

You messed up on 2 points. We're substituting "-4" into (y-k) so it would be (y-(-4) = (y+4). And the radius is 2, so \(2^{2}=4\)

Answer 16

ohhh I see now

Answer 17

one last question c: , I get 17.5 for this am I correct? https://prwi7873-stonewall-ccl.gradpoint.com/Resource/5711966,90A,0,0,0,0,0/Assets/testitemimages/geometry_b/circles/mc070-1.jpg

Answer 18

No idea.

Answer 19

darn , well ima just take a guess then XD thank you for your help!