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Find a recurrence relation and give initial conditions for the number of bit strings of length n that do not have two consecutive 0s. I'm lost on how to start this.
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The number of \(n\) bit binary strings can be thought of as two sets : 1) Strings that end in \(1\) 2) Strings that end in \(0\)
Let \(a_n\) denote the number of \(n\) bit strings that do not have two consecutive 0's
If the string ends in \(1\), then the \(n-1\)th bit could be either \(0\) or \(1\) so the number of \(n\) bit strings that end in \(1\) and do not have two consecutive \(0\)'s are \(a_{n-1}\) |dw:1434309606750:dw|
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