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OpenStudy (anonymous):
Thanks for helping!
Complex conjugate of z2=8(cos(7pi/6)+isin(7pi/6)))
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OpenStudy (anonymous):
@Hero @Michele_Laino @ganeshie8 @mathstudent55 @Nnesha @Loser66 @Luigi0210 @whpalmer4
OpenStudy (anonymous):
My worksheet says /z subscript 2. Which I think means complex conjugate.
OpenStudy (anonymous):
It gave me the z2 equation and just says /z2
OpenStudy (anonymous):
okay, thanks for attempting to help :)
OpenStudy (anonymous):
What does the x' and y' mean?
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OpenStudy (anonymous):
oh, gotcha
OpenStudy (anonymous):
So the conjugate is 2 sqrt(7)?
OpenStudy (anonymous):
Okay, thanks! That was pretty helpful.
OpenStudy (irishboy123):
*if* \( z_2=8\ (cos\frac {7 \pi}{6} \ + \ isin\frac{7\pi}{6})\), then \( \bar z_2=8\ (cos\frac {7 \pi}{6} \ - \ isin\frac{7\pi}{6})\)
OpenStudy (anonymous):
Oh, so it only needs a subtraction?
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OpenStudy (irishboy123):
@NotSephiroth
yes
\(z = x + i y\), \(\bar z = x - i y\)
OpenStudy (irishboy123):
or \(z = R e^{i \theta}\), \(\bar z = R e^{-i \theta}\)
OpenStudy (anonymous):
Okay thanks!
OpenStudy (anonymous):
that was really helpful!
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