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Physics 8 Online
OpenStudy (anonymous):

In the circuit shown, the greatest voltage drop will occur across which of the following resistors? R1, R2, R3, or R4 ?

OpenStudy (anonymous):

OpenStudy (michele_laino):

at the first step the equivalent circuit is: |dw:1434309387712:dw| where R_0 is such that: \[\Large {R_0} = \frac{1}{{\frac{1}{{13}} + \frac{1}{{18}}}} = ...\]

OpenStudy (anonymous):

ok! so we get 7.548 ?

OpenStudy (michele_laino):

ok! R_0=7.55 ohms

OpenStudy (anonymous):

yay:)

OpenStudy (michele_laino):

now the current is: \[\large I = \frac{V}{{{R_{TOTAL}}}} = \frac{{15}}{{8.5 + 3.2 + 7.55}} = ...\]

OpenStudy (anonymous):

so we get 0.779?

OpenStudy (michele_laino):

yes! we can round off that result to I=0.78 amperes

OpenStudy (anonymous):

ok! what does that mean then?

OpenStudy (michele_laino):

now we have the subsequent voltage drop: \[\large \begin{gathered} {V_1} = {R_1}I = 8.5 \times 0.78 = ... \hfill \\ {V_{AB}} = {R_{AB}}I = 7.55 \times 0.78 = ... \hfill \\ {V_4} = {R_4}I = 3.2 \times 0.78 = ... \hfill \\ \end{gathered} \]

OpenStudy (michele_laino):

drops*

OpenStudy (michele_laino):

|dw:1434309867660:dw|

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