Question

Suppose a magnetic field of 1.0 T is applied to an area within a circular loop of wire. The strength of the field is then increased to 4.0 T. By what factor is the magnetic flux changed?

A. 2

B. 4

C. 0.5

D. 0.25

Answer 1

magnetic flux is given by the subsequent formula:
\[\Large \Phi = BS\]

Answer 2

where S is the area enclosed by our circular loop

Answer 3

ok! what do we plug in?

Answer 4

so we have:
\[\Large \begin{gathered}
{\Phi _1} = 1 \times S = S \hfill \\
{\Phi _2} = 4 \times S = 4S \hfill \\
\hfill \\
\frac{{{\Phi _2}}}{{{\Phi _1}}} = \frac{{4S}}{S} = 4 \hfill \\
\end{gathered} \]

Answer 5

ohhh so our solution is 4? :O

Answer 6

yes!

Answer 7

yay! thanks!:)

Answer 8

:)