A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is:
H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4

Question

A 29.00−mL sample of an unknown H3PO4 solution is titrated with a 0.130M NaOH solution. The equivalence point is reached when 27.73mL of NaOH solution is added.What is the concentration of the unknown H3PO4 solution? The neutralization reaction is: 
H3PO4(aq)+3NaOH(aq)→3H2O(l)+Na3PO4

anonymous · Answer

first find the amount of moles of NaOH

anonymous · Answer

do you know how to do that?

anonymous · Answer

yes i did but it keeps telling me my answer is wrong

anonymous · Answer

what did you get?

anonymous · Answer

thats not what i got

anonymous · Answer

The first step is to find the number of moles of NaOH

anonymous · Answer

0.13 mol/L x 0.02773L = 4.688mol

anonymous · Answer

The molar ratio is 1:3

anonymous · Answer

so divide 4.688/3 = 1.563 mol of H3PO4

anonymous · Answer

The last step is to divide the moles by the volume

anonymous · Answer

1.563mol/0.029 L = 53.9 mol/L

anonymous · Answer

Does that work?

anonymous · Answer

no problem :)
Don't forget to metal

anonymous · Answer

*medal