please HELP me i will medal and fan.. The table below shows two equations: Equation 1 |3x − 1| + 7 = 2 Equation 2 |2x + 1| + 4 = 3 Which statement is true about the solution to the two equations? Equation 1 and equation 2 have no solutions. Equation 1 has no solution and equation 2 has solutions x = 0, 1. The solutions to equation 1 are x = −1.3, 2 and equation 2 has no solution. The solutions to equation 1 are x = −1.3, 2 and equation 2 has solutions x = 0, 1.
I THINK THAT IT IS D?!
Do you know the steps for solving absolute vale equations?
No not really
Ok.
you set the absolute value side equal to the other side as a Case #1. and set the absolute value side equal to the other side all times -1 as a Case #2
also, absolute value can never get to be negative
the answer has to be the third one
just by deduction
you don't even have to solve :)
hope this helps
Yes, but why is there no solution? there is always a solution
\[\left| -3 \right|= 3\] so the \[\left| x \right|= 3\] means that x could be -3 or positive 3
ok.. thanks!!
to solve for absolute values you need to write it as a positive value as well as a negative value \[\left| 3x-1 \right|+7 =2\]can be re-written as 3x - 1 + 7 = 2, 3x = -4, x = -4/3 = -1.33 and -(3x - 1) + 7 = 2 = -3x + 1 + 7 =2 -3x +8 = 2 -3x = -6 x = 2 Does this make sense?
Try following the same steps for the second equation \[\left| 2x + 1 \right| + 4 = 3\] If you post your work I'll help you through it.
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