Question

A coil with an area of 0.10 m^2 is in a magnetic field of 0.20 T perpendicular to its area. It is flipped through 180° so that the part that was up is down. The flip takes 1.0 s. Estimate the average induced emf between the ends of the coil while it is being flipped.

A. 0.020 V

B. 0.040 V

c. 0.0 V

D. 0.010 V

Answer 1

here the magnetic flux change is:
\[\Large \begin{gathered}
\Delta \Phi = \Phi \left( {\mathbf{B}} \right) - \Phi \left( { - {\mathbf{B}}} \right) = 2\Phi \left( {\mathbf{B}} \right) = \hfill \\
\hfill \\
= 2 \times 0.10 \times 0.20 = ...Weber \hfill \\
\end{gathered} \]

Answer 2

we get 0.04?so choice B? :O

Answer 3

no, since we have to compute the emf, which is given by the subsequent formula:
\[\Large E = \frac{{\Delta \Phi }}{{\Delta t}} = \frac{{0.04}}{1} = ...volts\]

Answer 4

ohh okay! that still gets 0.04 though? :/

Answer 5

yes! that's right!

Answer 6

yay! thanks!!:D

Answer 7

:)