How would you solve 3x-2y=12 using slope intercept form.
we need to isolate y right? so we need to subtract 3x from both sides now we have \[\huge~\rm-2y=-3x+12\] any cles on what the next step is?
the next step is to divide the left side by -2.
yes can you please do that? :)
I got -2y/-2 = 12-3x/-2 and then y = -6 -3x/-2 and the final answer is y = -6 - 3x/2. Is this correct?
-6? where did that come from?
I got -6 by doing 12/-2.
\[\huge~\rm~\frac{ −2y=−3x+12 }{ -2y=-2y-2y}\]
I did that except I didn't have it divided by -2y, I had -2 without the y.
keep in mind, when dividing by 2 negatives, the result is positive
y=-3/2x-6
Ah, so that means that the answer would be a positive -6+3x/2.
so yes :) good job! :)
y = 3/2x - 6
it need to be in y = mx + b form
\(\color{blue}{\text{Originally Posted by}}\) @pooja195 y=-3/2x-6 \(\color{blue}{\text{End of Quote}}\)
Alright, thanks you two!
it is not -3/2....it is 3/2
Right.
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