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Algebra
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@xapproachesinfinity
about what?
How to do it.
question?
Where is the question?
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I need help figuring out how to answer the question
Did any of you get the picture?
you mean the previous one \[\frac{\sqrt{9}}{\sqrt[6]{9}}\] what you need too use is the properrty \(\sqrt[n]{a}=a^{\frac{1}{n}}\)
No not the previous question
This question
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then after that use the property \(\frac{a^n}{a^m}=a^{n-m}\)
oh ok
@Ehsan18
I don't know how to use that property
well it is really the same stuff
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well if you have \[\sqrt{9}=9^{1/2}\] that's how you turn radical to power
Ok so how do I get the whole question?
\[\sqrt[4]{9}=9^{1/4}\]
well don't you know how to do \[a^n\times a^m=a^{n+m}\] use this for the top
Isn't this an exam Q? @Nicole2525
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