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Algebra 7 Online
OpenStudy (anonymous):

I need help!!!

OpenStudy (anonymous):

@xapproachesinfinity

OpenStudy (ehsan18):

about what?

OpenStudy (anonymous):

How to do it.

OpenStudy (xapproachesinfinity):

question?

OpenStudy (kash_thesmartguy):

Where is the question?

OpenStudy (anonymous):

I need help figuring out how to answer the question

OpenStudy (anonymous):

Did any of you get the picture?

OpenStudy (xapproachesinfinity):

you mean the previous one \[\frac{\sqrt{9}}{\sqrt[6]{9}}\] what you need too use is the properrty \(\sqrt[n]{a}=a^{\frac{1}{n}}\)

OpenStudy (anonymous):

No not the previous question

OpenStudy (anonymous):

This question

OpenStudy (xapproachesinfinity):

then after that use the property \(\frac{a^n}{a^m}=a^{n-m}\)

OpenStudy (xapproachesinfinity):

oh ok

OpenStudy (anonymous):

@Ehsan18

OpenStudy (anonymous):

I don't know how to use that property

OpenStudy (xapproachesinfinity):

well it is really the same stuff

OpenStudy (xapproachesinfinity):

well if you have \[\sqrt{9}=9^{1/2}\] that's how you turn radical to power

OpenStudy (anonymous):

Ok so how do I get the whole question?

OpenStudy (xapproachesinfinity):

\[\sqrt[4]{9}=9^{1/4}\]

OpenStudy (xapproachesinfinity):

well don't you know how to do \[a^n\times a^m=a^{n+m}\] use this for the top

OpenStudy (anonymous):

Isn't this an exam Q? @Nicole2525

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