Which of the following is an even function?
g(x) = (x – 1)2 + 1
g(x) = 2x2 + 1
g(x) = 4x + 2
g(x) = 2x
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OpenStudy (anonymous):
@Lokid
OpenStudy (anonymous):
@Kash_TheSmartGuy
OpenStudy (anonymous):
sorry i don't rember :/
OpenStudy (anonymous):
f(-a)=f(a)
then f(x) is an even function
OpenStudy (anonymous):
listen to that person ^
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OpenStudy (anonymous):
@fakeee I'm confused
OpenStudy (anonymous):
I am saying that f(x) is an even function, if it satisfies f(a)=f(-a) for any value of a.
for example, you have to have f(1)=f(-1)
OpenStudy (anonymous):
in your options, there is only one such function that satisfies f(-a)=f(a)
which on do you think it is and why?
OpenStudy (anonymous):
So it's A. g(x) = (x – 1)2 + 1 ?
OpenStudy (anonymous):
plug in a and -a into each option and set them equivalent to each other: (like this )
\((a-1)^2+1=(-a-1)^2+1\)
\(2(a)^2+1=2(-a)^2+1\)
\(4(a)+2=4(-a)+2\)
\(2(a)=2(-a)\)
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OpenStudy (anonymous):
can you tell me now which is that function that satisfies f(a)=f(-a) ?