Question

Suppose a magnetic field of 0.20 T is applied to the area within a circular loop of wire. The strength of the field is then changed to 0.10 T. By what factor is the magnetic flux changed?

1/2 , 1/4 , 2 , or 4

? :/

Answer 1

before variation, the magnetic flux is:
0.20 * S, where S is the area enclose by the circular loop
after the variation, the magnetic flux is:
0.10*S
so the magnetic flkux changing is:
\[\Delta \Phi = 0.2S - 0.1S = 0.1S\]

Answer 2

do you know the relation between the two?

Answer 3

and the requested ratio is:
\[\frac{{{\Phi _2}}}{{{\Phi _1}}} = \frac{{0.1S}}{{0.2S}} = ...\]

Answer 4

ohh okay! so then we get 1/2 as our solution?

Answer 5

yes! I think so!

Answer 6

yay! thanks!!:D

Answer 7

:)