Question

help me pls

Answer 1

how does the first equation turn into the second one?

Answer 2

\[\rm \sqrt{x}~can~also~be~written~as~x^{\frac{1}{2}}\]
\[\rm \sqrt{x}~.\sqrt{x}~also~be~written~as~x^{\frac{1}{2}}~.x^{\frac{1}{2}}-->x^{\frac{1}{2}+\frac{1}{2}}-->x^{1}-->x\]

Answer 3

so \(\Large\rm\sqrt{x}~.\sqrt{x}=x\)

Answer 4

ohh i get it now!

Answer 5

\[\sqrt{3}\times \sqrt{3}=3\]

Answer 6

Just multiply it out
[36 / sqrt(3)] * sqrt(3)/sqrt(3) =

The sqrt(3) * sqrt(3) = 3 So, that equals
[36 * sqrt(3)] / 3

Answer 7

correct @Mindblast3r :)

Answer 8

Hi MindBlast
I neatened up my answer and deleted that earlier answer.

Answer 9

wow you guys really helped a lot, and yea i saw @wolf1728

Answer 10

All The Best :)

Answer 11

Okay mind blast

Answer 12

Heck, I think rvc did some good work too!

Answer 13

you both did.

Answer 14

Thanks - that's why I awarded him my own medal.
And thank you mind blast

Answer 15

NP

Answer 16

okay - time to go
c ya

Answer 17

cya