Given: tangent to Circle O.
If m = 140°, then A =
70
110
140
http://assets.openstudy.com/updates/attachments/53739855e4b0530e83f03f38-tootsi123-1400084606214-group179.gif
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OpenStudy (anonymous):
@ganeshie8
OpenStudy (anonymous):
@geerky42
OpenStudy (anonymous):
@freckles
geerky42 (geerky42):
m = 140° ?
Do you mean \(m\angle C=140^\text o\)
OpenStudy (anonymous):
sorry, its m DB with an arch over that= 140
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OpenStudy (anonymous):
OpenStudy (anonymous):
would it be 140?
geerky42 (geerky42):
I think that refers to arc DAB (minor arc), right?
OpenStudy (anonymous):
right
geerky42 (geerky42):
In that case, then angle half the 140
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OpenStudy (anonymous):
so, because DB = 140 DAB = 140?
geerky42 (geerky42):
Sorry I am on laptop.
What I am trying to say is that given the information, we can see that angle C is half the measure of arc BD |dw:1434465275082:dw|
geerky42 (geerky42):
Then given ABCD is inscribed in circle, we know that sum of opposite angles is always 180, right?
geerky42 (geerky42):
Do you follow me?
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
and yes
geerky42 (geerky42):
Okay, then we have \(m\angle A+m\angle C = 180^\text o\)
geerky42 (geerky42):
we figured out that C is 70.
geerky42 (geerky42):
Right?
OpenStudy (anonymous):
right
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OpenStudy (anonymous):
wait, i got the answer. my teacher came by and just gave me it. thank you for your time!!! i understand it better now
OpenStudy (anonymous):
i had rather her explain it to me though
geerky42 (geerky42):
ok, answer is 110, right?
geerky42 (geerky42):
ok great!
OpenStudy (anonymous):
thats what she said. thanks again!
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