Ask your own question, for FREE!
Mathematics 8 Online
OpenStudy (anonymous):

Given: tangent to Circle O. If m = 140°, then A = 70 110 140 http://assets.openstudy.com/updates/attachments/53739855e4b0530e83f03f38-tootsi123-1400084606214-group179.gif

OpenStudy (anonymous):

@ganeshie8

OpenStudy (anonymous):

@geerky42

OpenStudy (anonymous):

@freckles

geerky42 (geerky42):

m = 140° ? Do you mean \(m\angle C=140^\text o\)

OpenStudy (anonymous):

sorry, its m DB with an arch over that= 140

OpenStudy (anonymous):

OpenStudy (anonymous):

would it be 140?

geerky42 (geerky42):

I think that refers to arc DAB (minor arc), right?

OpenStudy (anonymous):

right

geerky42 (geerky42):

In that case, then angle half the 140

OpenStudy (anonymous):

so, because DB = 140 DAB = 140?

geerky42 (geerky42):

Sorry I am on laptop. What I am trying to say is that given the information, we can see that angle C is half the measure of arc BD |dw:1434465275082:dw|

geerky42 (geerky42):

Then given ABCD is inscribed in circle, we know that sum of opposite angles is always 180, right?

geerky42 (geerky42):

Do you follow me?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

and yes

geerky42 (geerky42):

Okay, then we have \(m\angle A+m\angle C = 180^\text o\)

geerky42 (geerky42):

we figured out that C is 70.

geerky42 (geerky42):

Right?

OpenStudy (anonymous):

right

OpenStudy (anonymous):

wait, i got the answer. my teacher came by and just gave me it. thank you for your time!!! i understand it better now

OpenStudy (anonymous):

i had rather her explain it to me though

geerky42 (geerky42):

ok, answer is 110, right?

geerky42 (geerky42):

ok great!

OpenStudy (anonymous):

thats what she said. thanks again!

geerky42 (geerky42):

ok no problem

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!