check my work please
if f(x)= 3x+2 then, we have: f(2)= 3*2+2=8 so your answer is right
we have: \[{f^{ - 1}}\left( x \right) = \frac{{3x + 7}}{2}\]
so we get: \[{f^{ - 1}}\left( 3 \right) = \frac{{3 \times 3 + 7}}{2} = 8\]
question #3 if we add 2 to both sides, we have: \[\begin{gathered} 2y + 14 + 2 = 4y - 2 + 2 \hfill \\ \hfill \\ 2y + 16 = 4y \hfill \\ \end{gathered} \]
now we have to subtract 2y from both sides so we get: \[\begin{gathered} 2y + 16 - 2y = 4y - 2y \hfill \\ 16 = 2y \hfill \\ \end{gathered} \]
finally I divide both sides by 2, so I can write: \[\begin{gathered} \frac{{16}}{2} = \frac{{2y}}{2} \hfill \\ \hfill \\ y = 8 \hfill \\ \end{gathered} \]
so your answer is right!
no, I can't do what you ask to me, there is no reason for that
okay
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