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OpenStudy (michele_laino):
if f(x)= 3x+2
then, we have:
f(2)= 3*2+2=8 so your answer is right
OpenStudy (michele_laino):
we have:
\[{f^{ - 1}}\left( x \right) = \frac{{3x + 7}}{2}\]
OpenStudy (michele_laino):
so we get:
\[{f^{ - 1}}\left( 3 \right) = \frac{{3 \times 3 + 7}}{2} = 8\]
OpenStudy (michele_laino):
question #3
if we add 2 to both sides, we have:
\[\begin{gathered}
2y + 14 + 2 = 4y - 2 + 2 \hfill \\
\hfill \\
2y + 16 = 4y \hfill \\
\end{gathered} \]
OpenStudy (michele_laino):
now we have to subtract 2y from both sides so we get:
\[\begin{gathered}
2y + 16 - 2y = 4y - 2y \hfill \\
16 = 2y \hfill \\
\end{gathered} \]
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OpenStudy (michele_laino):
finally I divide both sides by 2, so I can write:
\[\begin{gathered}
\frac{{16}}{2} = \frac{{2y}}{2} \hfill \\
\hfill \\
y = 8 \hfill \\
\end{gathered} \]
OpenStudy (michele_laino):
so your answer is right!
OpenStudy (michele_laino):
no, I can't do what you ask to me, there is no reason for that