The figure below shows a shaded rectangular region inside a large rectangle: A rectangle of length 10 units and width 5 units is shown. Inside this rectangle is a smaller rectangle of length 4 units and width 2 units placed symmetrically inside the larger rectangle. The smaller rectangle is shaded gray. What is the probability that a point chosen inside the large rectangle is not in the shaded region? 8% 16% 50% 84%
bruh... i have no idea
@Luigi0210
@LegendarySadist
srry
\[\huge \frac{Area~of~unshaded~region}{Total~rectangle~area}\]
\[\large Area~of~unshaded~region~=~Total~rectangle~Area~-~Shaded~area\]
Now all you gotta do is calculate the rectangle areas and then use them in the formulas I put above. If you have any questions, just ask :)
C
I got d i ment
Yes, it would be D. Good job :)
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