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Chemistry 8 Online
OpenStudy (anonymous):

A 1.0 M H2S solution has a pH = 3.75 at equilibrium. What is the value of Ka?

OpenStudy (anonymous):

Find the concentration of the hydronium ion first. Can you do that?

OpenStudy (anonymous):

no I'm sorry idk how to do that. I forgot how

OpenStudy (anonymous):

@ghuczek could you explain how?

OpenStudy (anonymous):

\[\color{green}{[\mbox{H}_3\mbox{O}^+] = 10^{-pH}}\]

OpenStudy (anonymous):

Then, write the equation and the equilibrium expression.

OpenStudy (anonymous):

so it would be \[[H _{3}O+]=10^{-3.75} \] ?

OpenStudy (anonymous):

how would I then solve that

OpenStudy (anonymous):

Use a calculator. Raise ten to that exponent.

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