Question

NUmber 8

Answer 1

Hi!! What is the Number 8 for?

Answer 2

\[\infty\]

Answer 3

\[if \left(\begin{matrix}8-x^2 for -2\le x \le2 \\ x^2 else where,\end{matrix}\right) then \int\limits_{-1}^{3}f(x) dx is a number \between \]

Answer 4

is a number between?*
would you like to know the choices?

Answer 5

how would i do this?

Answer 6

ignore number 8

Answer 7

hmm i see peiewize function
and you the area under its curve

Answer 8

it is a peicewise

Answer 9

what 8 do yu want us to ignore?
8-x^2?
this should be part of the funtion

Answer 10

i am talking about the title of the question. that is what you should ignore

Answer 11

eh soka!

Answer 12

\[f(x) = \left\{\begin{array}{rcc}
8-x^2 & \text{if} & -2\leq x\leq 2\\
x^2& \text{otherwise} &
\end{array}
\right.
\]
just seeing if i could do it, ignore me

Answer 13

alright you just do some linearity here
see where you should integrate 8-x^2
and x^2

Answer 14

as you can see from -1<x<2
you can integrate 8-x^2

Answer 15

the rest 2 to 3 you integrate x^2

Answer 16

do you get it, or should i write it down?

Answer 17

i know the answer is 8

Answer 18

The question asks for what the answer could be between

Answer 19

\[\int_{-1}^{3}f(x)dx=\int_{-1}^{2}f(x)dx+\int_{2}^{3}f(x)dx\]
\[\int_{-1}^{2}(8-x^2)dx+\int_{2}^{3}x^2dx\]

Answer 20

The choices were a) 0 and 8
b) 8 and 16
c) 16 and 24
d) 24 and 32
e) 32 and 40

Answer 21

hmm i see so they separated it
you just do those two integral separately

Answer 22

\[\int_{-1}^{2}(8-x^2)dx=?\]

Answer 23

43/3

Answer 24

really how ?

Answer 25

the integral is 8x-(1/3)x^3

Answer 26

i found 62/3

Answer 27

i tried it again, it gave me 21

Answer 28

i made an arithmetic mistake.

Answer 29

yes 21 is good!

Answer 30

but then it is not in the choices

Answer 31

I believe the answer is B

Answer 32

Earlier,I said the solution to the intergral was 8 and i was wrong

Answer 33

something is wrong in what you wrote?
that way must work

Answer 34

can you post a snap shot of the problem please

Answer 35

is the function exately like missy wrote it

Answer 36

hey yo there?

Answer 37

???

Answer 38

i'm waiting...

Answer 39

sorry, i will do that now

Answer 40

now i got what is those btw mean
we need to add those two integrals and see the solution lies
btw what two points

Answer 41

i found 21 +19/3 =82/3
which lies
24<82/3<32

Answer 42

go with what we found in the first time
and add the other integral

Answer 43

see if you got same as me

Answer 44

just miss understood the problem

Answer 45

i got 21-(19/3)

Answer 46

hmm why -19/3?

Answer 47

never mind

Answer 48

we are good.

Answer 49

so D?

Answer 50

\[\int_{2}^{3}x^2ds=\frac{x^3}{3}=19/3\]

Answer 51

yes D

Answer 52

Instead of getting the sum of both integrals, I decided to do the difference.

Answer 53

yeah i see that :)

Answer 54

alright i think we solved that :)

Answer 55

Arigato!

Answer 56

No problem :)
yakoso