Question

MEDAL!!!!
6. Insert <,> B. < C. =

Answer 1

@nincompoop

Answer 2

@zepdrix

Answer 3

Hmm the bottoms are different :O Makes them difficult to compare.
Let's find the `least common multiple` of 4 and 7.

Answer 4

least common multiple is 1?

Answer 5

no no, thats the `greatest common factor` :)

Answer 6

if we count by 4's and count by 7's,
when do they meet? :)

Answer 7

28

Answer 8

4, 8, 12, 16, 20, 24, 28
7, 14, 21, 28

28 ah good!

Answer 9

So we want a bottom of 28.
\[\Large\rm \frac{3}{4}\cdot\color{royalblue}{\frac{7}{7}}\]See how this guy already has a 4 in the bottom? :d
so we gotta give him a 7, ya?

Answer 10

i see

Answer 11

so i mulitpy 3 and 4? 21/28

Answer 12

mmm ok looks good :d
how bout the other fraction?

Answer 13

21/49

Answer 14

\[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{?}{?}}\]

Answer 15

Hmm this bottom already has a 7.
I don't think we wanna give him another 7 in order to get to 28.

Answer 16

7/3

Answer 17

So we actually wanna give him a 4, ya?\[\Large\rm \frac{4}{7}\cdot\color{royalblue}{\frac{4}{4}}\]Because the 7 times 4 will give us that 28 that we were looking for.

Answer 18

ok

Answer 19

So what do you get for that second fraction? :)
Again, multiply top with top, bottom with bottom.

Answer 20

16/28

Answer 21

its B

Answer 22

i think

Answer 23

Ok good,
So instead of comparing \(\Large\rm \frac{3}{4}\) and \(\Large\rm \frac{4}{7}\)
we can get a common denominator and compare \(\Large\rm \frac{21}{28}\) and \(\Large\rm \frac{16}{28}\)

Answer 24

A~

Answer 25

>

Answer 26

the first one is bigger?
yay good job \c:/

Answer 27

thankyou <3