Question

If a 14-foot-diameter sheave is used to drive a cable car, at what angular velocity must sheave turn in order for the cable car to travel 11 miles per hour? Give your answer in revolution per minute.(1 mi = 5280ft)

Answer 1

radius=14/2=7
circumference C=2 pi r
\[=2*\frac{ 22 }{ 7 }*7=44ft.\]
no .of revolutions in 1 mile
\[=\frac{ 5280 }{ 44 }=120\]
no. of revolutions in 11 mile=120*11=1320
no. of revolutions in 1 hr.=1320
no. of revolutions per minute=1320/60=?

Answer 2

Thanks a lot

Answer 3

yw