Calculus 1 Question is attached.
Sorry, my internet connection suddenly slows down when i try to upload a picture.
4d?
sorry number 5
lol oh that is a choice \[\lim_{h \rightarrow 0}\frac{1}{k}\ln(\frac{2+h}{2})\]
I didn't realize it was a multiple choice thingy
\[F'(x)=f(x) \\ \int\limits_a^b f(x) dx=?\] What does F'=f mean? I will give you a hint that F is the ____-derivative of f.
I will also give you another hint: fundamental theorem of calculus
for example: how do you evaluate this: \[\int\limits_{1}^{2}x^2 dx\]
Since i know that the derivative of F(x) is itself i can just switch them around in the integral equation right?
recall: \[\frac{d}{dx}(\frac{x^3}{3})=x^2 \text{ for all } x \\ \ \text{ so } \int\limits_1^2 x^2 dx=[\frac{x^3}{3}]_1^2 =\frac{2^3}{3}-\frac{1^3}{3}\] you are given \[\frac{d}{dx}(F)=f \text{ for all } x \\ \int\limits_a^b f dx=[ ? ]_a^b\] and that f is continuous which is another important thing
but wouldnt, f(x) in your example be the same function as its derivative?
are you saying f=f'?
math is case sensitive so when they say F they don't mean f
so no we aren't given f'=f
do you know usually to integrate you need to find the antiderivative of the expression that is the integrand ?
so if we are given F'=f that means the antiderivative of f is F since F'=f
They do not give is the functions. but lets assume the function is e^x
did you not understand the example I gave above?
i did not understand it
\[\frac{d}{dx}(\frac{x^3}{3})=x^2 \text{ for all } x \\ \ \text{ so } \int\limits_1^2 x^2 dx=[\frac{x^3}{3}]_1^2 =\frac{2^3}{3}-\frac{1^3}{3}\] I started off exactly as your question did
replace the x^2 with f and replace the x^3/3 with F you can do this since (x^3/3)'=x^2 and (F)'=f
the problem with that is the fact that F and f are not the same for all values of x like the question stated.
No it is saying F'(x)=f(x) for all x
Also why do F and f have to be the same? You are definitely not given that.
F' and f have to be the same for all x
which they are because when you differentiate (x^3/3) you do get x^2
x^2=x^2 for all x
http://mathworld.wolfram.com/FundamentalTheoremsofCalculus.html This is just the fundamental theorem of calculus
Okay, I think I have a hard time understanding this because we never learned the fundamental principle of calculus and I am currently studying for the final, so that means my teacher never intended to teach that concept.
so you guys never cover definite integrals?
covered*
We did, but we were given the rules.
so have you ever done the one or know how to do the one I mentioned before: \[\int\limits_1^2 x^2 dx\]
We were not taught how to evaluate an integral using the definition.
like how would you tackle that one then?
I can do definite integrals. Why did you choose x^2? as one of the functions?
I can choose 1 or x is doesn't matter it is just an example
would e^x work then?
\[\int\limits_1^2 1 dx=?\] sure we can use whatever function that is continuous and has a continuous derivative
I just want to see what you do to evaluate something like that if you never been taught the fundamental theorem of calculus
Like do you not normally find the antiderivative of the integrand ?
answer is 1
I know but I want to know how you get there
like what steps do you take
ill draw what i did
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