Question

Help me please
screencap in comments.
best answer rewarded

Answer 1

1. simplify square roots to simplify the expression more:
\[((\sqrt{25}*\sqrt{3a})+(\sqrt{4}*\sqrt{3a})-(\sqrt{9}*\sqrt{3a}))/3a\]

Answer 2

Probably gonna get banned for saying this, but every time I read your question, I see "best answer retarded"

Answer 3

2. Next solve the square roots:
\[((5*\sqrt{3a})+(2*\sqrt{3a})-(3*\sqrt{3a})/\sqrt{3a}\]

Answer 4

Note: first step denominator should be square root 3a
3. the numerator has like terms so:
\[(5+2-3)(\sqrt{3a})/(\sqrt{3a})\rightarrow 5+2-3\rightarrow 4\]

Answer 5

as I mentioned plenty times before...there are different methods to solving the problem in Mathematics as long as it doesn't break the Math rules.

Answer 6

but.. @hughfuve your answer isn't in the choices given... so something is wrong.

Answer 7

because ... (I hope I still remember this right) when you're changing to exponent form \[\sqrt{3a} \rightarrow (3a)^{\frac{1}{2}}\]

Answer 8

you're distributing that 1/2 all over

Answer 9

Ok. I know what's going on.. we need a \[\sqrt{3a}\] in the numerator so we can cancel out the \[\sqrt{3a}\] denominator

Answer 10

so we need to split up 75, 27, and 12

Answer 11

\[\frac{\sqrt{75a}+\sqrt{12a}-\sqrt{27a}}{\sqrt{3a}}\]

Answer 12

ok this is going to work :)

we want that denominator to leave but before we have that we need to split up 75, 12, and 27.. we need perfect square numbers

Answer 13

is @Jravenv here right now?

I want to guide her through this process

we need to know
what perfect squares can we use so we can take the square root

so what is 3 x ? = 75, 3 x ? = 12, and 3 x ? = 27?

there are 3 perfect square numbers

Answer 14

another way is what's 75/3, 12/4 , and 27/3 ???

Answer 15

sorry 75/3, 12/3, and 27/3

Answer 16

114/3

Answer 17

this is separate
what is 75/3

or 3 x ? = 75

Answer 18

we're not adding those three fractions.. we are using division for
75/3 =?
12/3 =?
27/3 = ?

Answer 19

25

Answer 20

yes! so what about 12/3 = ? and 27/3 = ?

Answer 21

4 and 8 and a 3rd

Answer 22

what is 12 divided by 3?
what is 27 divided by 3?

Answer 23

4 and 9

Answer 24

\[\frac{\sqrt{25 \cdot 3 a}+\sqrt{4 \cdot 3a}-\sqrt{9 \cdot 3 a}}{\sqrt{3a}}\]

Answer 25

so all we need is the square root of 25, 4, and 9

what is the square root of 25?
what is the square root of 4?
what is the square root of 9?

Answer 26

5 2 and 3?

Answer 27

yes.

Answer 28

\[\frac{5\sqrt{ 3 a}+2\sqrt{ 3a}-3\sqrt{ 3 a}}{\sqrt{3a}}\]

Answer 29

now we noticed that there is a term in common and I want to factor it out because i want to get rid of the denominator.. so what can we pull out of the numerator?

Answer 30

each term in the numerator has it, so it's safe to factor out :)

Answer 31

I can't factor 5 2 and 3 out, but I can factor _____________?

Answer 32

3a

Answer 33

\[\frac{\sqrt{ 3 a}(5+2-3)}{\sqrt{3a}}\]

yes notice that now we can get rid of the square root ?

Answer 34

we're left with a very simple equation... using order of operations PEMDAS... well just AS...we just add and subtract.

Answer 35

So its 4

Answer 36

yes it's 4.
5+2-3

using order of operations..addition first
5+2 = 7
7-3 (subtraction)

7-3 = 4

Answer 37

geeez I completely forgot how to do that.. you are quite the doll usuki.